CuttingaPieceofColoredPaper

input:

30
128
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Code Solution:

package test;

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.util.Scanner;

/* đề bài là: cho 1 hình chữ nhật kích thước nxn chỉ gồm các giá trị 0 và 1
* nhiệm vụ là đếm xem có bao nhiêu hình chữ nhật con gồm toàn 0 và toàn 1
* giả sử 1 hcn 8×8 thì sẽ có tồn tại các hcn toàn 1 or toàn 0 vs kích thước 1×1, 2×2, 3×3, 4×4,5×5,6×6,7×7,8×8
* do mình quên ko copy đề bài vs test case mẫu nên mai sẽ lên cty copy đề vs test case mẫu về
* Hình như mình copy thiếu testcase nên code ko chạy được ấy
*/
public class CuttingaPieceofColoredPaper_CatGiay {
static int t, n, count1, count0;
static int[][] data;

static void backTrack(int x, int y, int length) {
int sum = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
sum += data[i][j];
}
}

if (sum == 0) {
count0++;
return;
}
if (sum == n * n) {
count1++;
return;
} else {
backTrack(x, y, length / 2);
backTrack(x, y + length / 2, length / 2);
backTrack(x + length / 2, y, length / 2);
backTrack(x + length / 2, y + length / 2, length / 2);
}
}

public static void main(String[] args) {
try {
System.setIn(new FileInputStream(“CuttingaPieceofColoredPaper_CatGiay.txt”));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Scanner sc = new Scanner(System.in);
t = sc.nextInt();
for (int tc = 1; tc <= t; tc++) {
n = sc.nextInt();
sc.nextLine();
//System.out.println(n);
data = new int[n + 1][n + 1];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
data[i][j] = sc.nextInt();
}
}
count0 = 0;
count1 = 0;
backTrack(0, 0, n);
System.out.println(“Case #” + tc + ” ” + count0 + ” ” + count1);
}
}

}

 

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